20x^2-10x-(15/4)=0

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Solution for 20x^2-10x-(15/4)=0 equation: 


x in (-oo:+oo)

20*x^2-(10*x)-(15/4) = 0

20*x^2-10*x-15/4 = 0

20*x^2-10*x-15/4 = 0

DELTA = (-10)^2-(-15/4*4*20)

DELTA = 400

DELTA > 0

x = (400^(1/2)+10)/(2*20) or x = (10-400^(1/2))/(2*20)

x = 3/4 or x = -1/4

x in { -1/4, 3/4 }

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